Making a conversion implicit by unwrapping it hands the operand to a
different target type, and a default literal takes its value from that
type: "S? x = new S?(default)" holds a value, while "S? x = default" is
null. Unwrapping the nullable constructor around a shortened literal
therefore turned "S? x = default(S)" into a null nullable. The literal is
spelled out again whenever unwrapping moves it to a type other than the one
it was shortened from.
Converting a using resource to the declared variable type is unconditional
now (except when the declaration says "var", which supplies no type): the
declaration always spells the type out, so any conversion to it may stay
implicit, which is also what shortens default(T) there.
Assisted-by: Claude:claude-opus-5[1m]:Claude Code
Christoph Wille