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For ProjectGuid project property, generate GUID in bracket form

Otherwise Visual Studio won't build the project
pull/422/head
Linquize 12 years ago
parent
commit
2790f6373c
  1. 2
      ILSpy/Languages/CSharpLanguage.cs
  2. 2
      ILSpy/VB/VBLanguage.cs

2
ILSpy/Languages/CSharpLanguage.cs

@ -317,7 +317,7 @@ namespace ICSharpCode.ILSpy @@ -317,7 +317,7 @@ namespace ICSharpCode.ILSpy
w.WriteAttributeString("DefaultTargets", "Build");
w.WriteStartElement("PropertyGroup");
w.WriteElementString("ProjectGuid", Guid.NewGuid().ToString().ToUpperInvariant());
w.WriteElementString("ProjectGuid", Guid.NewGuid().ToString("B").ToUpperInvariant());
w.WriteStartElement("Configuration");
w.WriteAttributeString("Condition", " '$(Configuration)' == '' ");

2
ILSpy/VB/VBLanguage.cs

@ -134,7 +134,7 @@ namespace ICSharpCode.ILSpy.VB @@ -134,7 +134,7 @@ namespace ICSharpCode.ILSpy.VB
w.WriteAttributeString("DefaultTargets", "Build");
w.WriteStartElement("PropertyGroup");
w.WriteElementString("ProjectGuid", Guid.NewGuid().ToString().ToUpperInvariant());
w.WriteElementString("ProjectGuid", Guid.NewGuid().ToString("B").ToUpperInvariant());
w.WriteStartElement("Configuration");
w.WriteAttributeString("Condition", " '$(Configuration)' == '' ");

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